How do you find the x and y intercept of #3 = 7x + -5y #?

Question

Genesis Allen · Accepted Answer

See the entire solution process below:

To find the #x# and #y# intercept you substitute #0# for one of the variables and solve for the other variable. x-intercept: Substitute #0# for #y# and solve for #x# #3 = 7x + (-5 * 0)# #3 = 7x + 0# #3 = 7x# #3/color(red)(7) = (7x)/color(red)(7)# #3/7 = (color(red)(cancel(color(black)(7)))x)/cancel(color(red)(7))# #3/7 = x# The x-intercept is: #3/7# or #(3/7, 0)# y-intercept: Substitute #0# for #x# and solve for #y# #3 = (7 * 0) + -5y# #3 = 0 - 5y# #3 = -5y# #3/color(red)(-5) = (-5y)/color(red)(-5)# #3/-5 = (color(red)(cancel(color(black)(-5)))y)/cancel(color(red)(-5))# #-3/5 = y# The y-intercept is: #-3/5# or #(0, -3/5)#

Jameson Allen · Answer

undefined To find the x-intercept, set y to zero and solve for x. To find the y-intercept, set x to zero and solve for y.

For the x-intercept:
3 = 7x + -5(0)
3 = 7x
x = 3/7

For the y-intercept:
3 = 7(0) + -5y
3 = -5y
y = -3/5