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How do you find the x and y intercept for #2x+6y=-12#?

Answer 1
Eva AbramsonEva Abramson

x- intercept #(-6,0)#
y-intercept #(0,-2)#

Given -

#2x+6y=-12#
To find the x-intercept put #y=0#
#2x+6(0)=-12#
#2x=-12#
#x=(-12)/2=-6#
x- intercept #(-6,0)#
To find the y-intercept put #x=0#
#2(0)+6y=-12#
#6y=-12#
#y=(-12)/6=-2#
y-intercept #(0,-2)#
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Answer 2
Eli AssoulineEli Assouline

To find the x-intercept, set y = 0 and solve for x: 2x + 6(0) = -12 2x = -12 x = -6

To find the y-intercept, set x = 0 and solve for y: 2(0) + 6y = -12 6y = -12 y = -2

So, the x-intercept is (-6, 0) and the y-intercept is (0, -2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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