How do you find the volume of the sphere in terms of #pi# given #V=4/3pir^3# and d= 9 ft?
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To find the volume of a sphere in terms of π given ( V = \frac{4}{3} πr^3 ) and the diameter ( d = 9 ) feet, first, you need to find the radius (( r )) using the formula for diameter (( d )):
( d = 2r )
Substitute the given diameter (( d = 9 ) feet) into the equation and solve for ( r ):
( 9 = 2r )
( r = \frac{9}{2} )
Now, substitute the value of ( r ) into the formula for volume (( V )):
( V = \frac{4}{3} π \left(\frac{9}{2}\right)^3 )
( V = \frac{4}{3} π \left(\frac{9}{2}\right) \left(\frac{9}{2}\right) \left(\frac{9}{2}\right) )
( V = \frac{4}{3} π \cdot \frac{729}{8} )
( V = \frac{243 π}{2} )
So, the volume of the sphere in terms of ( π ) is ( \frac{243 π}{2} ) cubic feet.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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