How do you find the Vertical, Horizontal, and Oblique Asymptote given #(x^2-64)/(x-8)#?

Answer 1

It doesn't have any.

The numerator factorizes to #(x-8)(x+8)# so you can cancel the #x-8#, so you are left with #x+8#. This is a straight line with gradient #1#, which, arguably, is a degenerate case of an oblique asymptote.
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Answer 2

To find the vertical asymptote, set the denominator equal to zero and solve for x. In this case, x - 8 = 0, so x = 8 is the vertical asymptote.

To find the horizontal asymptote, compare the degrees of the numerator and denominator. If the degree of the numerator is less than the degree of the denominator, the horizontal asymptote is y = 0. If the degrees are equal, divide the leading coefficients. In this case, since the degree of the numerator (2) is greater than the degree of the denominator (1), there is no horizontal asymptote.

To find the oblique (slant) asymptote, perform polynomial long division or synthetic division. In this case, divide x^2 - 64 by x - 8. The quotient is x + 8. Therefore, the oblique asymptote is y = x + 8.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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