How do you find the vertex of #y = x^2 - 2#?
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- What is the vertex of #y=(x-4) (x-2)+x#?
- How do you solve # x^2-x-1=0#?
- How do you solve using the completing the square method #y^2+4y-45=0#?
- How do you solve using the completing the square method #x^2 + 2x = 35#?
- The volume of this box is 288 cubic cm, and the height is 4 cm. the length is triple the height, how do you find the width?

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