How do you find the vertex of #f(x)= -x^2-3x-6#?
Vertex of
x at the vertex:
y at the vertex:
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To find the vertex of the quadratic function ( f(x) = -x^2 - 3x - 6 ), you can use the formula ( x = \frac{-b}{2a} ), where ( a ) is the coefficient of the quadratic term (( x^2 )), and ( b ) is the coefficient of the linear term (( x )). In this case, ( a = -1 ) and ( b = -3 ). Plug these values into the formula to find the x-coordinate of the vertex. Then, substitute this value back into the original function to find the corresponding y-coordinate.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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