Home > Algebra > Vertex Form of a Quadratic Equation

How do you find the vertex of #f(x)= -x^2-3x-6#?

Answer 1

The solution set(or vertex set) is: #S={-3/2,-15/4}#

The general formula for a quadratic function is: #y=Ax^2+Bx+C#

To find the vertex, we apply those formulas: #x_(vertex) = −b/(2a)# #y_(vertex)=−triangle/(4a)#

In this case: #x_(vertex) = - (-3)/(2* (-1)) = - (3/2) = -3/2# and #y_(vertex) = - ((-3)^2 -4 * (-1) * (-6)) / (4 *(-1))# #y_(vertex) = - (9 - 24)/ -4 = - (15/4) = -15/4#

So, the solution set(or vertex set) is: #S={-3/2,-15/4}#

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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