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How do you find the vertex of #f(x)=-5x^2+2x+7#?

Answer 1

Savannah Anderson

#(1/5,36/5)#

#"for the standard quadratic function"#

#• y=ax^2+bx+c; a!=0#

#"the x-coordinate of the vertex is "#

#x_(color(red)"vertex")=-b/(2a)#

#"for " f(x)=-5x^2+2x+7#

#a=-5,b=2" and " c=7#

#rArrx_(color(red)"vertex")=-2/(-10)=1/5#

#"substitute this value into f(x) for y-coordinate"#

#rArry_(color(red)"vertex")=-5(1/5)^2+2(1/5)+7#

#color(white)(rArryverte)=-1/5+2/5+35/5=36/5#

#rArrcolor(magenta)"vertex " =(1/5,36/5)#

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Answer 2

Jameson Allen

To find the vertex of the quadratic function f(x) = -5x^2 + 2x + 7, you can use the formula x = -b/(2a) to find the x-coordinate of the vertex, where a = -5 and b = 2 from the equation. Then, substitute the value of x into the original equation to find the corresponding y-coordinate of the vertex. Thus, the vertex of the function f(x) = -5x^2 + 2x + 7 is (0.2, 7.2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.