How do you find the vertex of a parabola #y= [x+9]^2-14#?
Vertex of
This is the vertex form of f(x).
x-coordinate of vertex: x = - 9 y-coordinate of vertex: y = - 14.
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To find the vertex of the parabola (y = (x+9)^2 - 14), you can use the formula (h = -\frac{b}{2a}) to find the x-coordinate of the vertex, where (h) is the x-coordinate of the vertex, and (a) and (b) are coefficients of the quadratic equation in the form (y = ax^2 + bx + c). Then, substitute the x-coordinate back into the equation to find the corresponding y-coordinate. So, in this case, (a = 1) and (b = 18). Thus, (h = -\frac{18}{2(1)} = -9). Now, substitute (x = -9) into the equation to find the y-coordinate of the vertex: (y = (-9 + 9)^2 - 14 = -14). Therefore, the vertex of the parabola is (-9, -14).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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