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How do you find the vertex of a parabola #y= -5[x+2]^2#?

Answer 1

Nathan Axel

The vertex is at #color(red)((-2,0)#.

The equation for a parabola is in the vertex form as follows:

#y = a(x - h)^2 + k#, where (#h, k#) is the vertex of the parabola.

We can rephrase your formula as

#y = -5(x+2)^2 + 0#

We can see that by contrasting your equation with the vertex form

#h = -2# and #k = 0#.

The vertex is at (#-2,0#).

graph{y = -5(x+2)^2 [-5,2 , -5, 2]} #

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Answer 2

Jameson Allen

To find the vertex of a parabola in the form y = a(x - h)^2 + k, the vertex is at (h, k). For the given equation y = -5(x + 2)^2, the vertex is (-2, 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.