# How do you find the vertex of a parabola # y= 1/3[x-1]^2+2 #?

The equation of a parabola in vertex form is

diagram{-1/3(x-1)^2+2 [-5, 6, -5, 5]}

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To find the vertex of a parabola in the form ( y = a(x - h)^2 + k ), where ( (h, k) ) is the vertex, follow these steps:

- Identify the values of ( h ) and ( k ) from the equation. In this case, ( h = 1 ) and ( k = 2 ).
- The vertex of the parabola is at ( (h, k) ), so the vertex of ( y = \frac{1}{3}(x - 1)^2 + 2 ) is at ( (1, 2) ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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