How do you find the vertex of a parabola #f(x) = -x^2 - 2x#?

Answer 1

The vertex is (-1, 1)

The form of the equation is standard.

Standard form of a parabola: #f(x)=ax^2+bx+c# #-1# would be a and #-2# would be b in this equation.
To find the vertex, do #(-b)/(2a), f(-b/(2a))#.
#2/(2*-1)#
#2/-2#
#-1#
#f(-1)=-(-1)^2-2*-1#
#f(-1)=-1+2#
#f(-1)=1#

(-1, 1) is the vertex.

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Answer 2

To find the vertex of the parabola (f(x) = -x^2 - 2x), you can use the formula (x = -\frac{b}{2a}) to find the x-coordinate of the vertex. Then substitute this x-value into the function to find the corresponding y-coordinate.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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