How do you find the vertex and the intercepts for #y = 4x^2 -8x + 10#?
Vertex (1, 6)
No x-intercepts.
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To find the vertex of the quadratic function y = 4x^2 - 8x + 10, you can use the formula for the x-coordinate of the vertex, which is given by x = -b/(2a), where 'a' is the coefficient of the x^2 term and 'b' is the coefficient of the x term. Substituting the values from the equation, you get x = -(-8)/(2*4) = 1. Plug this value of x back into the original equation to find the y-coordinate of the vertex.
To find the x-intercepts (also known as roots or zeros), set y = 0 and solve the resulting quadratic equation 4x^2 - 8x + 10 = 0 using the quadratic formula or factoring.
To find the y-intercept, simply plug in x = 0 into the equation y = 4x^2 - 8x + 10 and solve for y.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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