# How do you find the vertex and the intercepts for #f(x)=(x+3)^2#?

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To find the vertex of the function f(x) = (x + 3)^2, you can use the formula for the vertex of a parabola, which is (-b/2a, f(-b/2a)). In this case, a = 1 and b = 3.

To find the x-intercept, set f(x) = 0 and solve for x.

To find the y-intercept, plug in x = 0 into the function f(x).

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