# How do you find the vertex and the intercepts for #f(x) = -3x^2 - 6x - 2#?

Vertex (1, -11)

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To find the vertex of the quadratic function ( f(x) = -3x^2 - 6x - 2 ), you first need to determine the x-coordinate of the vertex, which is given by ( x = -\frac{b}{2a} ), where ( a ) and ( b ) are the coefficients of the quadratic equation. In this case, ( a = -3 ) and ( b = -6 ). Then, substitute these values into the formula to find ( x ).

To find the y-coordinate of the vertex, plug the ( x )-coordinate found in the previous step into the original function ( f(x) ).

To find the x-intercepts (or roots), set ( f(x) = 0 ) and solve for ( x ). You can use the quadratic formula or factor the quadratic equation if possible.

To find the y-intercept, simply plug in ( x = 0 ) into the function ( f(x) ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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