How do you find the vertex and intercepts for #y = (x – 3)^2 + 4#?
We use the equation.
Luckily for you, the equation is already in perfect vertex form. Therefore, it's an easy matter to find the vertex. Stated simply, the vertex of this equation can be found by taking the negative of the number inside of the parenthesis (so the negative of -3) as the x coordinate, and the normal value of the number outside of the parenthesis (so 4) and making a point out of them. Since the negative of -3 is 3, your point is: (3,4) That is stated simply. If you were to graph it, you would have to transform the parabola from its original mother function (x^2) to the right three and up 4 on the y axis.
To find the x intercept, plug in 0 for y and solve the equation by isolating x, to find the y intercept plug in 0 for x and solve b isolating y.
Hope this helps!
By signing up, you agree to our Terms of Service and Privacy Policy
To find the vertex of the parabola represented by the equation (y = (x - 3)^2 + 4), you first need to rewrite it in vertex form, which is (y = a(x - h)^2 + k), where ((h, k)) is the vertex of the parabola. In this case, the vertex is ((3, 4)).
To find the x-intercepts (or zeros) of the parabola, you set (y) to (0) and solve for (x).
(0 = (x - 3)^2 + 4)
This equation has no real solutions since the square of any real number is non-negative, and adding (4) to it ensures it is always positive. Therefore, the parabola does not intersect the x-axis, meaning it has no x-intercepts.
By signing up, you agree to our Terms of Service and Privacy Policy
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you find the vertex, axis of symmetry and intercepts of #f(x)=x^2+3x+7#?
- What is the vertex of #f(x)= -x^2 + 6x + 3#?
- How do you find the zeros, real and imaginary, of #y=x^2+32x-4# using the quadratic formula?
- How do you solve using completing the square method #x^2+2x-3=0#?
- How do you use the important points to sketch the graph of #y = x^2 − 6x + 1#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7