# How do you find the vertex and intercepts for #y = x^2 - 4x + 12#?

Vertex is at

x-intercept is absent.

x-intercept. x-intercept is absent.

graph{x^2-4x+12 [-40, 40, -20, 20]} [Ans]

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To find the vertex of the parabola represented by the equation y = x^2 - 4x + 12, use the formula x = -b / (2a), where a = coefficient of x^2 term, and b = coefficient of x term. Substitute the values of a and b into the formula to find the x-coordinate of the vertex. Then, substitute this value back into the original equation to find the corresponding y-coordinate. To find the x-intercepts, set y = 0 and solve for x. To find the y-intercept, plug in x = 0 into the equation.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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