How do you find the vertex and intercepts for #y=2x^2-7#?
Its vertex is
Its Y- intercept is also
Its X-intercepts are
Given -
We shall have it as
Vertex
X intercept
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To find the vertex and intercepts for the quadratic equation (y = 2x^2 - 7), you can follow these steps:
- Vertex: Use the formula (x = -b/(2a)) to find the x-coordinate of the vertex. Then, substitute this value into the equation to find the corresponding y-coordinate.
- x-intercepts (or roots): Set (y) equal to zero and solve for (x).
- y-intercept: Substitute (x = 0) into the equation and solve for (y).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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