# How do you find the vertex and intercepts for #x^2-10x-8y+33=0#?

Vertex

NO X-INTERCEPT

Moving

To get

Write as:

Write as:

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The above line is part of the process of completing the square.

Substituting

As the graph is of general shape

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To find the vertex and intercepts for the quadratic equation (x^2 - 10x - 8y + 33 = 0), first, rewrite the equation in the standard form of a quadratic equation, (y = ax^2 + bx + c). Then, use the formulas for finding the vertex, x-intercepts (zeros), and y-intercept.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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