How do you find the vector equation and the parametric equations of the line that passes through the points A (3, 4) and B (5, 5)?
vector eqn: parametric eqns:
assuming we are working in 2D only
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To find the vector equation of the line passing through points A (3, 4) and B (5, 5), you first find the direction vector by subtracting the coordinates of one point from the other. Then, you choose one of the points as the initial point. The parametric equations can be obtained using the initial point and the direction vector.
Direction vector ( \vec{d} = \langle 5-3, 5-4 \rangle = \langle 2, 1 \rangle )
Initial point ( A(3, 4) )
Vector equation: ( \vec{r} = \langle 3, 4 \rangle + t \langle 2, 1 \rangle )
Parametric equations: [ x = 3 + 2t ] [ y = 4 + t ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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