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How do you find the value of #[9+3(5-7)]div3#?

Answer 1

Levi Adams

#1#

#"when evaluating expressions with mixed operations there"# #"is a particular order that must be followed"#

#"follow the order as set out in the acronym PEMDAS"#

#["P-parenthesis (brackets),E-exponents (powers),"# #"M-multiplication, D-division, A-addition, S-subtraction "]#

#rArr[9+3(5-7)]-:3#

#=[9+3(-2)]-:3larrcolor(red)"inner parenthesis"#

#=[9+(3xx-2)]-:3#

#=[9+ (-6)]-:3larrcolor(red)"multiplication"#

#=[9-6]-:3#

#3-:3larrcolor(red)"parenthesis complete"#

#=1larrcolor(red)"division"#

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Answer 2

Everly Taylor

To find the value of [9 + 3(5 - 7)] ÷ 3:

First, evaluate the expression inside the parentheses: (5 - 7) = -2.
Then, multiply 3 by the result of step 1: 3 × (-2) = -6.
Next, add 9 to the result of step 2: 9 + (-6) = 3.
Finally, divide the result of step 3 by 3: 3 ÷ 3 = 1.

Therefore, the value of the expression is 1.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.