How do you find the value of #(12(52div2^2))/6-2/3#?

Answer 1

#76/3#

we have #(12(52-:2^2))/6 -2/3#
start with the operation between parentheses : #52-:2^2=52-:4 = 13#
we get #(12xx13)/6-2/3#
we simplify : #(6xx2xx13)/6 -2/3 = (2xx13)/1-2/3=26/1-2/3#
now it's easy : #(26xx3)/3-2/3=78/3-2/3=76/3#
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Answer 2

To find the value of the expression (12(52÷2^2))/6 - 2/3, follow the order of operations, known as PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction).

First, perform the operations inside the parentheses: 52 ÷ 2^2 = 52 ÷ 4 = 13.

Then, multiply 12 by 13, which equals 156.

Next, divide 156 by 6, which equals 26.

Then, subtract 2/3 from 26.

To subtract fractions, they need to have a common denominator. The denominator for 3 and 6 is 6. So, 2/3 is equivalent to 4/6.

Subtracting 4/6 from 26 gives 26 - 4/6, which equals 26 - 2/3.

Thus, the value of the expression is 26 - 2/3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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