How do you find the value?

#cos# #alpha/2# if #tan alpha= 40/9, (180 < alpha<270)#

Answer 1

#cos(alpha/2)=-4/sqrt41#

Given: #(180ltalpha<270)# indicating that #cosalpha # is negative
#tanalpha=40/9# opposite side is 40 adjacent side is 9 hypotenuse will be 41, because #sqrt(9^2+40^2)=sqrt(81+1600)=sqrt1681=41# #cosalpha="(adjacent side)/(hypotenuse)"# #cosalpha=-9/41# #cos(alpha/2)=+-sqrt((1+cosalpha)/2)=+-sqrt((1-9/41)/2# #=+-sqrt((41-9)/(41xx2))=+-sqrt(32/2xx1/41)=+-sqrt(16)/sqrt(41)#
#cos(alpha/2)=+-4/sqrt41#
As mentioned, #180^@ltalphalt270^@, # it follows that #180/2ltalpha/2<270/2#
#90ltalpha/2<135#, where #cos(alpha/2)# is negative
Hence, #cos(alpha/2)=-4/sqrt41#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

Start with the identity:

#tan^2(alpha) +1 = sec^2(alpha)#
Substitute #sec^2(alpha)= 1/cos^2(alpha)#
#tan^2(alpha)+ 1= 1/cos^2(alpha)#
Multiply both sides by #cos^2(alpha)/(tan^2(alpha) + 1)#:
#cos^2(alpha) = 1/(tan^2(alpha) + 1)#

Use the square root operation on both sides:

#cos(alpha) = +-sqrt(1/(tan^2(alpha) + 1))#
We are told that #180^@ < alpha < 270^@#, therefore we choose the negative value:
#cos(alpha) = -sqrt(1/(tan^2(alpha) + 1))#

Add 1 to both sides:

#1+ cos(alpha) = 1-sqrt(1/(tan^2(alpha) + 1))#
Multiply both sides by #1/2#:
#(1+ cos(alpha))/2 = (1-sqrt(1/(tan^2(alpha) + 1)))/2#

Use the square root operation on both sides:

#+-sqrt((1+ cos(alpha))/2) = +-sqrt((1-sqrt(1/(tan^2(alpha) + 1)))/2)#
Substitute #+-sqrt((1+ cos(alpha))/2)= cos(alpha/2)#
#cos(alpha/2) = +-sqrt((1-sqrt(1/(tan^2(alpha) + 1)))/2)#
From #180^@ < alpha < 270^@# we derive #90^@ < alpha/2 < 135^@# and conclude that the cosine function is negative within the specified domain:
#cos(alpha/2) = -sqrt((1-sqrt(1/(tan^2(alpha) + 1)))/2)#
Substitute #tan^2(alpha) = (40/9)^2#:
#cos(alpha/2) = -sqrt((1-sqrt(1/((40/9)^2 + 1)))/2)#

I used WolframAlpha to simplify the above into an exact form:

#cos(alpha/2) = -(4sqrt41)/41#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

To find the value of something, you typically need to apply relevant mathematical operations or procedures based on the given context of the problem or question. This may involve calculations, manipulations of equations, or using known formulas or principles depending on the specific problem you're trying to solve. It's essential to carefully analyze the information provided and determine the appropriate method or approach to find the desired value accurately.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7