How do you find the unit rate for a snail that can go 13 inches in 20 seconds?

Answer 1

#13# inches in #20# seconds is equivalent to #39# inches/minute.

Since there are #3# period of #20# seconds in a minute or #(13" inches")/(cancel(20)cancel(" seconds")) xx (cancel(60)^3cancel(" seconds"))/(1" minute") = (39" inches")/("minute")#
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Answer 2

To find the unit rate for a snail that can go 13 inches in 20 seconds, divide the total distance by the total time:

[ \text{Unit rate} = \frac{13 \text{ inches}}{20 \text{ seconds}} = 0.65 \text{ inches/second} ]

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Answer 3

To find the unit rate for a snail that can go 13 inches in 20 seconds, divide the distance traveled by the time taken. So, the unit rate would be 13 inches divided by 20 seconds, which equals 0.65 inches per second.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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