How do you find the sum or difference of #(2ab-3a+4b)+(5a+4ab)#?

Answer 1

See a solution process below:

First, remove all of the terms from parenthesis. Be careful to handle the signs of each individual term correctly:

#2ab - 3a + 4b + 5a + 4ab#

Next, group like terms:

#-3a + 5a + 2ab + 4ab + 4b#

Now, combine like terms:

#(-3 + 5)a + (2 + 4)ab + 4b#
#2a + 6ab + 4b#
If necessary, you can factor a #2# out of each term giving:
#(2 * a) + (2 * 3ab) + (2 * 2b)#
#2(a + 3ab + 2b)#
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Answer 2

To find the sum or difference of the given expressions, you need to combine like terms:

(2ab - 3a + 4b) + (5a + 4ab)

Combine like terms:

2ab + 4ab = 6ab -3a + 5a = 2a

So, the sum or difference is:

6ab + 2a + 4b

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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