How do you find the sum of the unit vectors (2,2,7) and (5, -6, 2)?

Answer 1

Since the given #(2,2,7)# and #(5,-6,2)# are not unit vectors it is not clear what was intended by this question.

Possibility 1: Sum of the unit vectors with the same orientation as the given values Since #sqrt(2^2+2^2+7^2)=sqrt(57)# the unit vector corresponding to #(2,2,7)# is #color(white)("XXX")(2/sqrt(57),2/sqrt(57),7/sqrt(57))#
Similarly the unit vector corresponding to #(5,-6,2)# is #color(white)("XXX")(5/sqrt(65),-6/sqrt(65),2/sqrt(65))#
The sum of these unit vectors is #color(white)("XXX")(2/sqrt(57)+5/sqrt(65),2/sqrt(57)-6/sqrt(65),7/sqrt(57)+2/sqrt(165))# (these terms could be evaluated but given the question's ambiguity I have not bothered with the effort involved)
Possibility 2: Unit vector with the same orientation as the sum of the given vectors #(2,2,7)+(5,-6,2)=(7,-4,9)# with corresponding unit vector: #color(white)("XXX")(7/sqrt(146),-4/sqrt(146),9/sqrt(146))#
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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