# How do you find the sum of #Sigma (k+1)^2(k-3)# where k is [2,5]?

By signing up, you agree to our Terms of Service and Privacy Policy

To find the sum of Σ(k+1)^2(k-3) where k ranges from 2 to 5, you substitute the values of k into the expression and add them together.

Σ(k+1)^2(k-3) = (2+1)^2(2-3) + (3+1)^2(3-3) + (4+1)^2(4-3) + (5+1)^2(5-3) = (3)^2(-1) + (4)^2(0) + (5)^2(1) + (6)^2(2) = 9(-1) + 16(0) + 25(1) + 36(2) = -9 + 0 + 25 + 72 = 88

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- How do you find the antiderivative of #(cosx+secx)^2#?
- How do you use the second fundamental theorem of Calculus to find the derivative of given #int cos(sqrt( t))dt# from #[6, x]#?
- How do I evaluate the indefinite integral #intsin^2(2t)dt# ?
- What is #int (x^3-2x^2+6x+9 ) / (-x^2- x +3 )#?
- How do you evaluate the integral #int_0^(pi/4)cos(x)dx# ?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7