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How do you find the sum of #Sigma i^2# where i is [0,4]?

Answer 1

Charles Arocha

The sum is equal to #30#.

This sigma notation is asking to sum up all square numbers from #0# to #4#.

I'll write out the whole notation:

#color(white)=sum_(i=0)^4i^2#

#=0^2+1^2+2^2+3^2+4^2#

#=0+1+4+9+16#

#=1+4+9+16#

#=5+9+16#

#=14+16#

#=30#

That's the result. I hope this helped!

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Answer 2

Paisley Johnson

To find the sum of ( \sum_{i=0}^{4} i^2 ), you simply substitute the values of ( i ) from 0 to 4 into the expression ( i^2 ) and then add them together:

[ \sum_{i=0}^{4} i^2 = 0^2 + 1^2 + 2^2 + 3^2 + 4^2 ]

[ = 0 + 1 + 4 + 9 + 16 ]

[ = 30 ]

So, the sum of ( \sum_{i=0}^{4} i^2 ) is 30.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.