How do you find the square root of 25?

Answer 1

#sqrt(25) = 5#

A square root of a number #n# is a number #r# such that #r^2 = n#
In the case of #25# we find that #5^2 = 25#, so #5# is a square root of #25#.
Note that #-5# is also a square root of #25#, in that:
#(-5)^2 = (-5)xx(-5) = 25#

The positive square root, also referred to as the principal square root, is typically referred to as "the" square root.

We write the following in symbols:

#sqrt(25) = 5#
Note that #sqrt(...)# refers to the principal square root. If we want to say that either square root can be used, we could write #+-sqrt(...)#
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Answer 2

The square root of 25 is 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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