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How do you find the solution to the quadratic equation #x^2 - x +2 =0#?

Answer 1

ote that there are no Real solutions to the quadratic equation #x^2-x+2 = 0#

Applying the quadratic root formula #x = (-b+-sqrt(b^2-4ac))/(2a)#

we find the roots #x = (1+-sqrt(-7))/2# which can be evaluated using Complex numbers as #x = (1+sqrt(7)i)/2# or #x=(1-sqrt(7)i)/2#

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Answer 2

Julia Adams

To find the solutions to the quadratic equation (x^2 - x + 2 = 0), you can use the quadratic formula, which is (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}), where (a = 1), (b = -1), and (c = 2):

Substitute the values of (a), (b), and (c) into the quadratic formula:

(x = \frac{{-(-1) \pm \sqrt{{(-1)^2 - 4(1)(2)}}}}{{2(1)}})

(x = \frac{{1 \pm \sqrt{{1 - 8}}}}{2})

(x = \frac{{1 \pm \sqrt{{-7}}}}{2})

Since the discriminant ((b^2 - 4ac)) is negative, the solutions will be complex.

The solutions are:

(x = \frac{1}{2} + \frac{\sqrt{7}i}{2}) and (x = \frac{1}{2} - \frac{\sqrt{7}i}{2})

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.