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How do you find the solution to the quadratic equation #4x^2-13x+3=0#?

Answer 1

Nathan Axel

#4x^2-13x+3 = 0#

The left side has a fairly simple factoring #(4x-1)(x-3) = 0#

So either #4x-1 = 0 rarr x=1/4# or #x-3=0 rarr x=3#

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Answer 2

Avery Alexander

To find the solution to the quadratic equation (4x^2 - 13x + 3 = 0), you can use the quadratic formula: (x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}}), where (a = 4), (b = -13), and (c = 3). Plugging these values into the formula, you can calculate the solutions for (x).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.