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How do you find the solution set for x² + 10x + 25 = 64?

Answer 1

Avery Alexander

#x^2+10x-39=0#

#x^2+13x-3x-39=0#

#x(x+13)-3(x+13)=0#

#=>(x+13)(x-3)=0#

#x=-13,3#

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Answer 2

Eva Adamson

To find the solution set for the equation (x^2 + 10x + 25 = 64), you can follow these steps:

Step 1: Rewrite the equation in standard form, setting it equal to zero: [x^2 + 10x + 25 - 64 = 0] [x^2 + 10x - 39 = 0]

Step 2: Factor the quadratic equation (if possible) or use the quadratic formula. In this case, the quadratic equation can be factored as follows: [(x + 13)(x - 3) = 0]

Step 3: Set each factor equal to zero and solve for (x): [x + 13 = 0 \implies x = -13] [x - 3 = 0 \implies x = 3]

Step 4: Write the solution set containing the values of (x): [Solution , Set: {x = -13, , x = 3}]

So, the solution set for the equation (x^2 + 10x + 25 = 64) is ({x = -13, , x = 3}).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.