How do you find the solution set for #2/3a - 1/5a = 2#?

Answer 1

If you multiply both sides by #15# you can clear the denominators and solve as a simple integer equation to get:
#color(white)("XXXX")##a= 30/7 = 4 2/7#

Given #2/3a-1/5a=2#
Multiply both sides by #15# #color(white)("XXXX")##10a - 3a = 30# Simplify the left side #color(white)("XXXX")##7a = 30# Divide both sides by #7# #color(white)("XXXX")##a = 30/7
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Answer 2

To find the solution set for ( \frac{2}{3}a - \frac{1}{5}a = 2 ), first combine like terms on the left side:

( \frac{2}{3}a - \frac{1}{5}a = \frac{10}{15}a - \frac{3}{15}a = \frac{7}{15}a )

Then, solve for ( a ):

( \frac{7}{15}a = 2 )

Multiply both sides by ( \frac{15}{7} ):

( a = 2 \times \frac{15}{7} = \frac{30}{7} )

So, the solution set for the equation is ( a = \frac{30}{7} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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