How do you find the slope & y-intercept of the equation #3x + 5y = 15#?

Question

Savannah Anderson · Accepted Answer

Slope is # -3/5# and y-intercept is #3#

# 3x+5y=15 # [Use y as the topic]

y = -3/5x+3# or 5y=-3x+ 15#

contrasting with the straight line #y=mx+c# slope intercept form

Here, the y-intercept is #c=3#, and the slope is #m= -3/5#.

Consequently, the y-intercept is #3# and the slope is # -3/5#.

graph{3x+5y=15 [-5, 5, 10, -10]} [Ans]

Jace Anderson · Answer

undefined To find the slope-intercept form of the equation $ 3x + 5y = 15 $, first solve for $ y $. Then, identify the coefficients of $ x $ and $ y $ to determine the slope and y-intercept.

$$ 3x + 5y = 15 $$
$$ 5y = -3x + 15 $$
$$ y = -\frac{3}{5}x + 3 $$

The slope ($ m $) is the coefficient of $ x $, which is $ -\frac{3}{5} $. 
The y-intercept ($ b $) is the constant term, which is $ 3 $.

Therefore, the slope is $ -\frac{3}{5} $ and the y-intercept is $ 3 $.

Julia Adams · Answer

undefined To find the slope and y-intercept of the equation $3x + 5y = 15$, rearrange the equation into slope-intercept form ($y = mx + b$), where $m$ is the slope and $b$ is the y-intercept.

First, solve for $y$:
$$5y = -3x + 15$$
$$y = -\frac{3}{5}x + 3$$

The slope ($m$) is $-\frac{3}{5}$, and the y-intercept ($b$) is 3.

How do you find the slope &amp; y-intercept of the equation #3x + 5y = 15#?

How do you find the slope & y-intercept of the equation #3x + 5y = 15#?