How do you find the slope & yintercept of the equation #2x+y=5#?
y=2x+5#cancel(2x)cancel(2x)
"with yintercept "=5" and slope "=2" on graph{2x+5 [20, 20, 10, 10]}
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To find the slope and yintercept of the equation 2x + y = 5, you need to rewrite it in slopeintercept form, which is y = mx + b, where m is the slope and b is the yintercept. First, subtract 2x from both sides to isolate y, resulting in y = 2x + 5. From this, we can see that the slope (m) is 2 and the yintercept (b) is 5.
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To find the slopeintercept form (y = mx + b) of the equation 2x + y = 5:

Rewrite the equation in slopeintercept form by isolating y: Subtract 2x from both sides: y = 2x + 5

Now, the equation is in the form y = mx + b, where: m is the slope and b is the yintercept.
So, the slope (m) of the equation is 2, and the yintercept (b) is 5.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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