How do you find the slope that is perpendicular to the line #y = (-4/5)x + 1#?

Answer 1

The slope of the perpendicular line is #5/4#

Here the slope of the line is #m_1=-4/5#. Let the slope of the perpendicular line be #m_2#. We know condition of perpendicularity of two lines is #m_1*m_2=-1 or m_2= -1/m_1=-1/(-4/5)=5/4#[Ans]
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Answer 2

#+5/4#

Consider the standard form equation of: #" "y=mx+c# where #m# is the gradient (slope).
A line perpendicular to this has the gradient #" "(-1)xx1/m = -1/m#
In your equation #m=-4/5#
So #-1/m = +5/4#
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Answer 3

To find the slope perpendicular to a given line, take the negative reciprocal of the slope of the given line. In this case, the slope of the given line is ( -\frac{4}{5} ). So, the slope perpendicular to it would be the negative reciprocal, which is ( \frac{5}{4} ). Therefore, the slope perpendicular to the line ( y = -\frac{4}{5}x + 1 ) is ( \frac{5}{4} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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