How do you find the slope that is perpendicular to the line #y=(-3x)#?

Answer 1

Slope of the perpendicular: #color(green)(1/3)#

The standard general form of a linear equation in slope-intercept form is: #color(white)("XXX")y=color(green)(m)x+color(blue)(b)# with slope #color(green)(m)# and y-intercept #color(blue)(b)#.
The given equation #y=(-3x)# can be re-written to be in explicit slope-intercept form as: #color(white)("XXX")y=color(green)(""(-3))x+color(blue)(0)# with slope #color(green)(""(-3))#
If a line has a slope of #color(m)# then all lines perpendicular to it have a slope of #color(green)(""(-1/m))#
Since #y=-3x# has a slope of #color(green)(m=-3)# any line perpendicular to it will have a slope of #color(white)("XXX")color(green)((-1/m)=-(1/(-3))=1/3#
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Answer 2

To find the slope perpendicular to the line ( y = -3x ), take the negative reciprocal of the slope of the given line. The slope of ( y = -3x ) is -3, so the perpendicular slope is ( \frac{1}{3} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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