How do you find the slope that is perpendicular to the line #y=3x+2 #?

Answer 1

Any line with gradient #-1/3# will be perpendicular to the line #y = 3x + 2#.

(it should have the form #y = -1/3 x + b#, where b is an arbitrary number)

To find the equation of perpendicular lines, find the reciprocal of the gradient (in this case #1/3#) and multiply it by #-1#. To check, the gradient of the original line multiplied by the gradient of the new line should be equal to #-1#.
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Answer 2

The slope that is perpendicular to the line ( y = 3x + 2 ) can be found by taking the negative reciprocal of the slope of the given line. In this case, the slope of the given line is 3, so the slope of the line perpendicular to it is ( -\frac{1}{3} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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