How do you find the slope that is perpendicular to the line # x - 2y = 7#?

Answer 1

The slope of the line perpendicular to the given straight line is -2

Two striaght line are perpendicular if the product of their slopes is -1  Given the equation of the straight line  #x−2y=7 # #-2y=7−x # #y=(-x)/(-2)+7/(-2)# #y=x/2-7/2# The slope of the given straight line is a=1/2 , the slope of the line perpendicular line a':
#a⋅a'=−1 # #(1/2)*a'=−1 # #a'=−2#
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Answer 2

The slope of a line perpendicular to a given line is the negative reciprocal of the slope of the given line. To find the slope of the given line, x - 2y = 7, we need to rewrite it in slope-intercept form, y = mx + b, where m is the slope.

First, solve for y in the given equation: x - 2y = 7 -2y = -x + 7 y = (1/2)x - 7/2

Now, the slope of the given line is 1/2. The slope of a line perpendicular to this is the negative reciprocal of 1/2, which is -2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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