# How do you find the slope perpendicular to (-7,2) and (5,-12)?

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To find the slope perpendicular to a given line, first calculate the slope of the given line using the formula:

[ m = \frac{{y2 - y1}}{{x2 - x1}} ]

Then, determine the negative reciprocal of this slope to find the slope perpendicular to the given line. So, if the slope of the given line is ( m ), the slope perpendicular to it is ( -\frac{1}{m} ).

Using the coordinates (-7,2) and (5,-12), the slope of the given line is:

[ m = \frac{{-12 - 2}}{{5 - (-7)}} = \frac{{-14}}{{12}} = -\frac{7}{6} ]

The slope perpendicular to this line is the negative reciprocal of ( -\frac{7}{6} ), which is:

[ -\frac{1}{{-\frac{7}{6}}} = \frac{6}{7} ]

So, the slope perpendicular to the line passing through (-7,2) and (5,-12) is ( \frac{6}{7} ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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