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How do you find the slope perpendicular to #5x+2y=10#?

Answer 1

Avery Alexander

The slope of the perpendicular line is #=2/5#

Given -

#5x+2y=10#

Slope of the given line is #m_1=-a/b=-5/2#

Two lines are perpendicular when #m_1 xx m_2=-1#

Then

#m_2=-1/m_1=-1-:-5/2=-1xx-2/5=2/5#

#m_2=2/5#

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Answer 2

Abigail Allen

To find the slope perpendicular to a given line, you first need to determine the slope of the given line. The equation of the given line is typically in the form ( Ax + By = C ). To find the slope of the given line, rearrange the equation into slope-intercept form, ( y = mx + b ), where ( m ) represents the slope. Once you have the slope of the given line, the slope of the line perpendicular to it is the negative reciprocal of the slope of the given line. In this case, the given equation is ( 5x + 2y = 10 ), which can be rewritten as ( 2y = -5x + 10 ) and then ( y = -\frac{5}{2}x + 5 ). Therefore, the slope of the given line is ( -\frac{5}{2} ). The slope of the line perpendicular to it is the negative reciprocal of ( -\frac{5}{2} ), which is ( \frac{2}{5} ). Therefore, the slope perpendicular to ( 5x + 2y = 10 ) is ( \frac{2}{5} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.