How do you find the slope passing through (-1,-1), (-1,-5)?
See a solution process below:
A vertical line has an arbitrary slope by definition.
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To find the slope passing through (-1, -1) and (-1, -5), you use the formula for slope: (m = \frac{y_2 - y_1}{x_2 - x_1}). Substituting the given points, you get (m = \frac{-5 - (-1)}{-1 - (-1)}). Simplifying, you get (m = \frac{-5 + 1}{-1 + 1} = \frac{-4}{0}). Since the denominator is zero, the slope is undefined. This indicates that the line is vertical, parallel to the y-axis.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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