How do you find the slope of #x+8y=16#?
Put the equation back in the form of the slope-intercept:
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To find the slope of the equation x + 8y = 16, rearrange it into slope-intercept form, y = mx + b, where m is the slope.
First, subtract x from both sides to isolate 8y:
8y = -x + 16
Then, divide both sides by 8 to solve for y:
y = (-1/8)x + 2
The slope (m) is the coefficient of x, which is -1/8. Therefore, the slope of the equation x + 8y = 16 is -1/8.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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