How do you find the slope of #x+ 2y = 4#?

Answer 1

Slope #= -1/2#

Method 1: Based on knowledge of relation between standard form and slope Given a linear equation in standard form: #color(white)("XXX")Ax+By=C# the slope is #color(white)("XXX")m=-A/B#
Method 2: Conversion of linear standard form into slope-intercept form Slope-intercept form is #color(white)("XXX")y=mx+b# with slope #m# (and y-intercept(b))
Given #2+2y=4# #color(white)("XXX")2y=-x+4#
#color(white)("XXX")y=-1/2x+2# which is the slope-intercept form with slope #(-1/2)#
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Answer 2

To find the slope of the equation x + 2y = 4, rearrange the equation into slope-intercept form (y = mx + b), where m is the slope:

  1. Subtract x from both sides: 2y = -x + 4

  2. Divide all terms by 2 to isolate y: y = (-1/2)x + 2

The coefficient of x, which is -1/2, represents the slope. So, the slope of the equation x + 2y = 4 is -1/2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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