# How do you find the slope of the tangent line to the curve #4xy^3+3xy=7# at the point (1,1) by using imlicit differentiation?

I found: Slope

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To find the slope of the tangent line using implicit differentiation, differentiate the equation with respect to x, then solve for dy/dx. The equation is (4xy^3 + 3xy = 7). Differentiating with respect to x yields (4y^3 + 12xy^2(dy/dx) + 3y + 3x(dy/dx) = 0). Plug in the point (1,1) to find the value of dy/dx, which represents the slope of the tangent line at that point.

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