# How do you find the slope of the tangent line at point (2, 1) for #y=(x^2+1)#?

There is no such thing.

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To find the slope of the tangent line at a specific point on a curve, we can use the derivative of the function. The derivative of y = (x^2 + 1) with respect to x is 2x.

To find the slope of the tangent line at point (2, 1), we substitute x = 2 into the derivative.

Therefore, the slope of the tangent line at point (2, 1) for y = (x^2 + 1) is 2(2) = 4.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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