How do you find the slope of the straight line that passes through (–2, –4) and (3, –5)?

Answer 1

slope#=-1/5#

To find the slope (gradient) of the line passing through the 2 points use the #color(blue)"gradient formula"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(m=(y_2-y_1)/(x_2-x_1))color(white)(a/a)|)))# where #(x_1,y_1)" and " (x_2,y_2)" are 2 points"#

let # (x_1,y_1)=(-2,-4)" and " (x_2,y_2)=(3,-5)#

#rArrm=(-5-(-4))/((3-(-2)))=(-1)/5=-1/5#

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Answer 2

Julia Adams

To find the slope of the straight line passing through the points (-2, -4) and (3, -5), you can use the slope formula:

Slope (m) = (y2 - y1) / (x2 - x1)

Substitute the coordinates of the points into the formula:

m = (-5 - (-4)) / (3 - (-2))

Calculate:

m = (-5 + 4) / (3 + 2) m = (-1) / (5)

So, the slope of the line is -1/5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.