# How do you find the slope of the secant lines of #y=2x^2+sec(x)# at #x=0# and #x= pi?#

The secant line between two points on a curve (there is only one such line), is the straight line between the two points on the curve.

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To find the slope of the secant line of (y = 2x^2 + \sec(x)) at (x = 0) and (x = \pi), first, find the corresponding y-values by substituting (x = 0) and (x = \pi) into the equation. Then, use the formula for slope:

[ \text{Slope} = \frac{\text{change in } y}{\text{change in } x} ]

Subtract the y-values and x-values obtained for (x = 0) and (x = \pi) and use them in the slope formula to calculate the slope of the secant line.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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