# How do you find the slope of the secant lines of #f(x) = -x^2# through the points: [-2, -4]?

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To find the slope of the secant line of ( f(x) = -x^2 ) through the points ([-2, -4]), you use the slope formula:

[ \text{Slope} = \frac{\text{change in } y}{\text{change in } x} ]

Substitute the coordinates ((-2, -4)) into the formula:

[ \text{Slope} = \frac{-4 - f(-2)}{-2 - (-2)} ]

Evaluate (f(-2)) to get:

[ \text{Slope} = \frac{-4 - (-4)}{-2 - (-2)} ]

[ \text{Slope} = \frac{0}{0} ]

Since (0/0) is an indeterminate form, you need to simplify the expression or apply other techniques to find the slope. You can use the difference quotient or calculate the slope at another point close to (-2).

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