# How do you find the slope of the secant lines of #f(x)=6.1x^2-9.1x# through the points: x=8 and x=16?

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To find the slope of the secant line of ( f(x) = 6.1x^2 - 9.1x ) through the points ( x = 8 ) and ( x = 16 ), you first need to find the corresponding y-values of the function at these two x-values, and then use the slope formula:

[ \text{Slope} = \frac{{\text{Change in y}}}{{\text{Change in x}}} ]

Substitute the values into the formula:

[ \text{Slope} = \frac{{f(16) - f(8)}}{{16 - 8}} ]

Calculate ( f(16) ) and ( f(8) ), then find the difference in y-values, and finally divide it by the difference in x-values to find the slope of the secant line.

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To find the slope of the secant line of ( f(x) = 6.1x^2 - 9.1x ) through the points ( x = 8 ) and ( x = 16 ), you first need to find the corresponding y-coordinates for these x-values by substituting them into the function. Then, use the formula for slope: ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ), where ( (x_1, y_1) ) and ( (x_2, y_2) ) are the coordinates of the two points. Substituting the given values into the formula will give you the slope of the secant line.

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